MGVCL Exam Paper (30-07-2021 Shift 1)
Recently, Dr. Subir Vithal Gokarn passed away due to illness. He is a/an ___

Former Finance Minister
Former RBI Deputy Governor
Former Chief Minister of Gujarat
Former IAS Officer

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
___ is the rms value of the total current comprising the AC and DC components of the current in the circuit breaker pole at the instant of contact separation.

Symmetrical short circuit current
Symmetrical breaking current
Making current
Asymmetrical breaking current

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
A single phase motor connected to 400 V, 50 Hz supply takes 30 A at a power factor of 0.7 lagging. Calculate the capacitance required in parallel with the motor to raise the power factor to 0.9 lagging.

89.5 μF
99.5 μF
79.5 μF
69.5 μF

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
મારુતારુંનો ઝગડો હજી ખતમ થયો નથી, ચારપાંચ વર્ષ થઇ ગયા અને રાતદિવસ સાથે ઉઠવા-બેસવાનું તો ચાલુ જ છે. ઉપરોક્ત વાક્યમાં ક્યા ક્યા વ્યાકરણીય સમાસનો ઉપયોગ કરાયો છે?

દ્વન્દ્વ
અવ્યવીભાવ, મધ્યમપદલોપી
દ્વન્દ્વ, મધ્યમપદલોપી
તત્પુરુષ,

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
The expression for voltage regulation of a short transmission line for lagging power factor is given by: ___, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resistance and 'X' is the line reactance.

(IR cosφ_r - IX sinφ_r)/V_r
(IX cosφ_r - IR sinφ_r)/V_r
(IX cosφ_r + IR sinφ_r)/V_r
(IR cosφ_r + IX sinφ_r)/V_r

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'.

Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A
Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A
Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A
Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP