MGVCL Exam Paper (30-07-2021 Shift 1) In which of the following States, Tarapur Nuclear Power Plant is located? Assam Bihar Maharashtra Uttar Pradesh Assam Bihar Maharashtra Uttar Pradesh ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Determine maximum permissible load which a 15 MVA, ONAN cooled transformer to IS : 2026 can take for 6 hr, if the initial load on it was 12 MVA. The weighted ambient temperature is 20˚C. Assume the permissible load kVA as a fraction of rated kVA is 1.25. 18.75 MVA 9.6 MVA 12 MVA 15 MVA 18.75 MVA 9.6 MVA 12 MVA 15 MVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Maximum permissible load = Rated MVA rating*fraction of rated kVAMaximum permissible load = 15*1.25Maximum permissible load = 18.75 MVA
MGVCL Exam Paper (30-07-2021 Shift 1) The expression for voltage regulation of a short transmission line for lagging power factor is given by: ___, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resistance and 'X' is the line reactance. (IR cosφ_r + IX sinφ_r)/V_r (IR cosφ_r - IX sinφ_r)/V_r (IX cosφ_r + IR sinφ_r)/V_r (IX cosφ_r - IR sinφ_r)/V_r (IR cosφ_r + IX sinφ_r)/V_r (IR cosφ_r - IX sinφ_r)/V_r (IX cosφ_r + IR sinφ_r)/V_r (IX cosφ_r - IR sinφ_r)/V_r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For lagging power factor = (IR*cosφ + Ixsinφ)/VrFor leading power factor = (IR*cosφ - Ixsinφ)/VrZero voltage regulation occurs on leading power factor only.
MGVCL Exam Paper (30-07-2021 Shift 1) The Prime Minister Rozgar Yojana (PMRY) was launched in which year? 1993 1995 2003 2005 1993 1995 2003 2005 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The frequency of the emf in the stator of a 4-pole induction motor is 50 Hz, and that in the rotor is 2 Hz. What is the slip and at what speed is the motor running? 3%, 1440 rpm 3%, 1455 rpm 4%, 1440 rpm 4%, 1455 rpm 3%, 1440 rpm 3%, 1455 rpm 4%, 1440 rpm 4%, 1455 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rotor frequency, f_r = s*f_ss = 2/50s = 0.04Ns = 120f/PNs = 1500 rpms = (Ns - Nr)/NsNr = Ns(1 - s)Nr = 1500*(1 - 0.04)Nr = 1440 rpm
MGVCL Exam Paper (30-07-2021 Shift 1) 1 terabyte is equal to None of these 1024 kilobytes 1024 gigabytes 1024 bytes None of these 1024 kilobytes 1024 gigabytes 1024 bytes ANSWER DOWNLOAD EXAMIANS APP
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