MGVCL Exam Paper (30-07-2021 Shift 1) Which of the following architectures is also known as "Five Principles of Peaceful Co-existence"? Panchayatana Vedanga Panchsheel Manusmriti Panchayatana Vedanga Panchsheel Manusmriti ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series aiding. 1135 mH 1270 mH 730 mH 932 mH 1135 mH 1270 mH 730 mH 932 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance (M) = k*√(L1*L2)k = 0.45M = 0.45*√(900*100*10⁻⁶) = 135 mHLeq = L1 + L2 + 2MLeq = 900 + 100 + 270Leq = 1270 mH
MGVCL Exam Paper (30-07-2021 Shift 1) Choose the word which expresses nearly the opposite meaning of the given word "QUANDARY " Certainty Dilemma Clutch Embarrassment Certainty Dilemma Clutch Embarrassment ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) By inserting a plate of dielectric material between the plates of a parallel plate capacitor at constant potential, the energy stored in the capacitor is increased five times. The dielectric constant of the material is 5 1/5 25 1/25 5 1/5 25 1/25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Energy stored by capacitor, Q = ½CV²Dielectric constant is directly proportional to C and capacitance is proportional to the dielectrical constant
MGVCL Exam Paper (30-07-2021 Shift 1) Choose the best option from the given alternatives which can be substituted for the given word/sentenceA disease prevailing in a locality Habitat Host Epic Endemic Habitat Host Epic Endemic ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 600 kW 150 kW 450 kW 300 kW 600 kW 150 kW 450 kW 300 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
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