MGVCL Exam Paper (30-07-2021 Shift 1) નીચેના રુઢિપ્રયોગોને અર્થ સાથે સાંકળી જોડી બનાવો.1. કાન કરડવા - 1. બાતમી મળી જવી.2. કાન ફૂંકવા - 2. વાત પર ધ્યાન ન આપવું.૩. કાને વાત પહોચવી - ૩. કાન 1-42-33-14-2 1-32-43-14-2 1-32-23-44-1 1-22-33-44-1 1-42-33-14-2 1-32-43-14-2 1-32-23-44-1 1-22-33-44-1 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) જ્વાળા: ધુમાડો:: બરફ : ___ તાપમાન ગરમી બાષ્પ શીતળતા તાપમાન ગરમી બાષ્પ શીતળતા ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) In a single phase energy meter, the series electromagnet is energized by a ___ of ___ current coil, thick wire of few turns voltage coil, thick wire of few turns current coil, thin wire of more turns voltage coil, thin wire of more turns current coil, thick wire of few turns voltage coil, thick wire of few turns current coil, thin wire of more turns voltage coil, thin wire of more turns ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The series electromagnet is energized by a coil known as current coil which is connected in series with the load so that it carry the load current.The flux produced by this magnet is proportional to and in phase with the load current.
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
MGVCL Exam Paper (30-07-2021 Shift 1) Two-wattmeter method is used to measure the power taken by a 3-phase induction motor on no load. The wattmeter readings are 375 W and –50 W. Calculate the reactive power taken by the load. 325√3 VAR 425/√3 VAR 325/√3 VAR 425√3 VAR 325√3 VAR 425/√3 VAR 325/√3 VAR 425√3 VAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Reactive power taken, Q = √3*(W1 - W2)Q = √3*(375 + 50)Q = √3*425 kVAR
MGVCL Exam Paper (30-07-2021 Shift 1) Choose the word which best expresses the similar meaning of the given word " CALLOW" Immature Calm Mature Sophisticated Immature Calm Mature Sophisticated ANSWER DOWNLOAD EXAMIANS APP
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