MGVCL Exam Paper (30-07-2021 Shift 1) At what range of wind speed is the electricity from the wind turbine is generated? 250 – 450 mph 450 – 650 mph 100 – 125 mph 30-35 mph 250 – 450 mph 450 – 650 mph 100 – 125 mph 30-35 mph ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For small turbine starts generating power 12.6 kph (3.5 m/s) is the typical cut-in speed.At 36–54 kph (10–15 m/s) produces maximum generation power.At 90 kph (25 m/s) maximum, the turbine is stopped or braked.
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
MGVCL Exam Paper (30-07-2021 Shift 1) Which of the following are the advantages of Aerial Bunched Cables (ABC)? Higher safety and reliability Elimination of theft of energy All of these Reduced height of supports Higher safety and reliability Elimination of theft of energy All of these Reduced height of supports ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Who has won the ‘World Games Athlete Of the Year 2019’ ? Stanislav Horuna Rhea Stinn Rani Rampal Marina Chernova Stanislav Horuna Rhea Stinn Rani Rampal Marina Chernova ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) If a 415 V, 50 Hz, star-connected, three-phase squirrel-cage induction motor is operated from a 415 V, 70 Hz supply, the torque that the motor can now provide while drawing rated current from the supply reduces remains the same increases increases or reduces depending upon the rotor resistance reduces remains the same increases increases or reduces depending upon the rotor resistance ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Calculate the capacitance per meter of a 50 Ω load cable that has an inductance of 50 nH/m. 20 pF 30 pF 40 pF 10 pF 20 pF 30 pF 40 pF 10 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Z = √(L/C)C = L/Z²C = 50*10⁻⁹/(50*50)C = 0.02 nFC = 20 pF
EXAMIANS