MGVCL Exam Paper (30-07-2021 Shift 1) At what range of wind speed is the electricity from the wind turbine is generated? 450 – 650 mph 30-35 mph 250 – 450 mph 100 – 125 mph 450 – 650 mph 30-35 mph 250 – 450 mph 100 – 125 mph ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For small turbine starts generating power 12.6 kph (3.5 m/s) is the typical cut-in speed.At 36–54 kph (10–15 m/s) produces maximum generation power.At 90 kph (25 m/s) maximum, the turbine is stopped or braked.
MGVCL Exam Paper (30-07-2021 Shift 1) Murray loop test is performed on a faulty cable 300 m long. At balance, the resistance connected to the faulty core was set at 15 Ω and the resistance of the resistor connected to the sound core was 45 Ω. Calculate the distance of the fault point from the test end. 75 m 450 m 225 m 150 m 75 m 450 m 225 m 150 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,R2 is the resistance connected to the faulty core in ohmR2 is the resistance of the resistor connected to the sound core in ohmR1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)= (15/60)*600= 150 m
MGVCL Exam Paper (30-07-2021 Shift 1) 1 terabyte is equal to 1024 kilobytes None of these 1024 bytes 1024 gigabytes 1024 kilobytes None of these 1024 bytes 1024 gigabytes ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Fill in the blanks with suitable Preposition from the given alternatives.The match was dedicated ___ Indian fast bowler Zaheer, who has announced his retirement from international cricket to against from since to against from since ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series aiding. 1135 mH 932 mH 730 mH 1270 mH 1135 mH 932 mH 730 mH 1270 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance (M) = k*√(L1*L2)k = 0.45M = 0.45*√(900*100*10⁻⁶) = 135 mHLeq = L1 + L2 + 2MLeq = 900 + 100 + 270Leq = 1270 mH
MGVCL Exam Paper (30-07-2021 Shift 1) In the following question, one part of the sentence may have an error. Find out which part of the sentence has an error and select the option corresponding to it. If the sentence contains no error, Select "No error'' option. (Avoid punctuation errors)(A) Bubin together with / (B) her parents are coming / (C) to attend the party. / (D) NO ERROR D C B A D C B A ANSWER DOWNLOAD EXAMIANS APP
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