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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to

35
37
42
30

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

601/55
55/601
120/11
11/120

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are:

4, 8, 12
10, 20, 30
10, 20, 30
5, 10, 15

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

1015
689
268
432

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015

Problems on H.C.F and L.C.M
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

208
308
508
408

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Other number = (11 x 7700/275) = 308.

Problems on H.C.F and L.C.M
Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

17004
18002
18000
18004

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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