Problems on H.C.F and L.C.M Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are: 4, 8, 12 5, 10, 15 10, 20, 30 10, 20, 30 4, 8, 12 5, 10, 15 10, 20, 30 10, 20, 30 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 4128/4386 to its lowest terms 16/17 13/17 13/18 14/13 16/17 13/17 13/18 14/13 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the H.C.F. of 513, 1134 and 1215. 63 27 42 58 63 27 42 58 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1134 ) 1215 ( 1 1134 --------- 81 ) 1134 ( 14 81 --------- 324 324 --------- x ---------- H.C.F. of 1134 and 1215 is 81.So, Required H.C.F. = H.C.F. of 513 and 81. ______81 ) 513 ( 6 __486____ 27) 81 ( 3 81 0H.C.F. of given numbers = 27.
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: 1 Cannot be calculated 117 equal to their H. F 1 Cannot be calculated 117 equal to their H. F ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 9:22:08 hrs 7:25:14 hrs 10:13:17 hrs 8:27:12 hrs 9:22:08 hrs 7:25:14 hrs 10:13:17 hrs 8:27:12 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1080 1085 1095 1075 1080 1085 1095 1075 ANSWER DOWNLOAD EXAMIANS APP
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