Problems on H.C.F and L.C.M Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers. 295, 243 95, 43 395, 343 195, 143 295, 243 95, 43 395, 343 195, 143 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required numbers be 15.x and 11x.Then, their H.C.F. is x. So, x = 13.The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.
Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 98 100 97 99 98 100 97 99 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
Problems on H.C.F and L.C.M The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 91 1001 1911 910 91 1001 1911 910 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: Cannot be calculated equal to their H. F 1 117 Cannot be calculated equal to their H. F 1 117 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the L.C.M. of 16, 24, 36 and 54. 189 321 432 228 189 321 432 228 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2 | 16 - 24 - 36 - 54----------------------------- 2 | 8 - 12 - 18 - 27----------------------------- 2 | 4 - 6 - 9 - 27 --------------------------- 2 | 2 - 3 - 9 - 27 -------------------------- 2 | 1 - 3 - 9 - 27-------------------------- 3 | 1 - 1 - 3 - 9--------------------------- 3 | 1 - 1 - 1 - 3 L.C.M. = 2 x 2 x 2 x 3 x 3 x 2 x 3 = 432.
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is 1008 1022 1015 1032 1008 1022 1015 1032 ANSWER DOWNLOAD EXAMIANS APP
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