Problems on H.C.F and L.C.M Find the L.C.M of 2/15, 3/10, 6/5 7/5 8/5 6/5 2/3 7/5 8/5 6/5 2/3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is: 1015 432 268 689 1015 432 268 689 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015
Problems on H.C.F and L.C.M Find the smallest number of five digits exactly divisible by 16,24,36 and 54. 10268 10468 10368 10568 10268 10468 10368 10568 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Smallest number of five digits is 10000. Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432, On dividing 10000 by 432,we get 64 as remainder. Required number = 10000 +( 432 – 64 ) = 10368.
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M The H.C.F of two numbers is 8. Which of the following can never be their L.C.M? 60 56 48 24 60 56 48 24 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers. 295, 243 195, 143 395, 343 95, 43 295, 243 195, 143 395, 343 95, 43 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required numbers be 15.x and 11x.Then, their H.C.F. is x. So, x = 13.The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.
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