Problems on H.C.F and L.C.M Find the L.C.M of 2/15, 3/10, 6/5 2/3 8/5 7/5 6/5 2/3 8/5 7/5 6/5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the smallest number which when diminished by 8, is divisible by 9, 6, 12 and 18? 44 50 60 45 44 50 60 45 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 22 23 21 24 22 23 21 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M The H.C.F of two numbers is 8. Which of the following can never be their L.C.M? 48 24 60 56 48 24 60 56 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the H.C.F. of 513, 1134 and 1215. 27 42 58 63 27 42 58 63 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1134 ) 1215 ( 1 1134 --------- 81 ) 1134 ( 14 81 --------- 324 324 --------- x ---------- H.C.F. of 1134 and 1215 is 81.So, Required H.C.F. = H.C.F. of 513 and 81. ______81 ) 513 ( 6 __486____ 27) 81 ( 3 81 0H.C.F. of given numbers = 27.
Problems on H.C.F and L.C.M Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder . 1683 4683 2683 3683 1683 4683 2683 3683 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5,6,7,8 = 840. Required number is of the form 840k + 3 Least value of k for which (840k + 3) is divisible by 9 is k = 2. Required number = (840 X 2 + 3)=1683
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