Problems on H.C.F and L.C.M Find the least number which when divided by 16, 18, 20 and 2 leaves 4 as remainder in each case , but when divided by 7 leaves no. remainder 18000 18002 18004 17004 18000 18002 18004 17004 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12, 15, 18 and 27. 8720 8760 9720 9620 8720 8760 9720 9620 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 17004 18004 18002 18000 17004 18004 18002 18000 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two digits number is 2160 and their HCF is 12. The numbers are: (96,25) (72,30) (36,60) (12,180) (96,25) (72,30) (36,60) (12,180) ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 14. The least number which when diminished by 7 is divisible by 21, 28, 36 and 45 is? 1267 1265 1261 68 1267 1265 1261 68 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 30 10 20 40 30 10 20 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
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