Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12,15,18 and 27. 6720 8720 9720 7720 6720 8720 9720 7720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . Required number = (9999-279) = 9720.
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: 408 308 508 208 408 308 508 208 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = (11 x 7700/275) = 308.
Problems on H.C.F and L.C.M H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is: 360 1260 540 180 360 1260 540 180 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A. B. and C. start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds.all starting at the same point. 26 minutes 18 seconds 46 minutes 12 seconds. 45 minutes 42 minutes 36 seconds 26 minutes 18 seconds 46 minutes 12 seconds. 45 minutes 42 minutes 36 seconds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 4 5 6 3 4 5 6 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to: 601/55 55/601 120/11 11/120 601/55 55/601 120/11 11/120 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS