Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12,15,18 and 27. 8720 7720 6720 9720 8720 7720 6720 9720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . Required number = (9999-279) = 9720.
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 10 30 40 20 10 30 40 20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again? 240 seconds 243 seconds 242 seconds 246 seconds 240 seconds 243 seconds 242 seconds 246 seconds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is: 48 18 36 24 48 18 36 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.So, the numbers 12 and 16.L.C.M. of 12 and 16 = 48.
Problems on H.C.F and L.C.M A wholesale tea dealer 408 kilograms, 468 kilograms and 516 kilograms of three different qualities of tea. He wants it all to be packed into boxes of equal size without mixing. Find the capacity of th 12 24 50 36 12 24 50 36 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 23/37 11/13 17/29 31/45 23/37 11/13 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
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