Find the largest number of four digits exactly divisible by 12,15,18 and 27.

• A. 6720
• B. 7720
• C. 8720
• D. 9720

Answer: (D)

The Largest number of four digits is 9999.       Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.      On dividing 9999 by 540,we get 279 as remainder .   Required number = (9999-279) = 9720.