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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is

4
6
8
12

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the HCF of 2.1, 1.05 and 0.63

1.21
0.21
3.21
2.21

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

To solve this question quickly, first remove decimal by multiplying each term with 100,Then terms become 210, 105, 63Then HCF of above terms is 21, So Answer is 0.21

Problems on H.C.F and L.C.M
Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case

7
13
4
9

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is

540
180
360
1260

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case

707
505
606
404

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

  3 |  6 - 7  - 8  - 9 - 12-----------------------------  4 | 2  - 7  - 8  - 3 - 4  ---------------------------   2 | 2  - 7  - 2  - 3 - 1 --------------------------     | 1  - 7  - 1  - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505   

Problems on H.C.F and L.C.M
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

20
10
40
30

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.

MORE MCQ ON Problems on H.C.F and L.C.M

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