Problems on H.C.F and L.C.M The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is 4 6 12 8 4 6 12 8 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M HCF of 3/16, 5/12, 7/8 is: 3/47 2/47 5/48 1/48 3/47 2/47 5/48 1/48 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 2 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
Problems on H.C.F and L.C.M he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 91 910 1001 1911 91 910 1001 1911 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, 11 : 31 am 10 : 31 am 12 : 31 am 9 : 31 am 11 : 31 am 10 : 31 am 12 : 31 am 9 : 31 am ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 60 and 62 seconds is 1860 seconds1860/60 = 31 minutesThey will beep together at 10:31 a.m.Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 6 3 5 4 6 3 5 4 ANSWER DOWNLOAD EXAMIANS APP
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