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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is

1032
1022
1008
1015

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is:

3
5
6
4

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Problems on H.C.F and L.C.M
What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder?

121
123
112
116

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time  to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123

Problems on H.C.F and L.C.M
The least number which when increased by 5 each divisible by each one of 24, 32, 36 and 54 is :

859
4320
427
869

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Problems on H.C.F and L.C.M
Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.

24
21
31
17

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31

Problems on H.C.F and L.C.M
Which of the following has most number of divisors?

176
101
182
99

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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