Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is 1022 1032 1015 1008 1022 1032 1015 1008 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The least number which when divided by 8, 12 and 16, leave in each remainder 3, is? 71 69 51 70 71 69 51 70 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The Smallest number which when diminished by 7, is divisible by 12,16,18,21 and 28 is : 1032 1015 1008 1022 1032 1015 1008 1022 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three numbers are in the ratio 3:4:5 and their L.C.M is 2400. Their H.C.F is: 120 40 80 200 120 40 80 200 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 869 427 859 4320 869 427 859 4320 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS