Problems on H.C.F and L.C.M The product of two digits number is 2160 and their HCF is 12. The numbers are: (96,25) (36,60) (12,180) (72,30) (96,25) (36,60) (12,180) (72,30) ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 111 101 185 107 111 101 185 107 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M LCM of 455, 117, 338 is: 10670 106470 104670 107470 10670 106470 104670 107470 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 4 5 3 6 4 5 3 6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers are in the ratio 3 : 4. If their L.C.M. is 96. what is sum of the numbers? 84 56 76 48 84 56 76 48 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case? 19 18 16 17 19 18 16 17 ANSWER DOWNLOAD EXAMIANS APP
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