Problems on H.C.F and L.C.M The product of two digits number is 2160 and their HCF is 12. The numbers are: (96,25) (12,180) (72,30) (36,60) (96,25) (12,180) (72,30) (36,60) ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is: 360 540 1260 180 360 540 1260 180 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 131 133 127 129 131 133 127 129 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 1 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds 2 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16,20, and 24, is : 1600 11400 6400 3600 1600 11400 6400 3600 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 443 389 548 216 443 389 548 216 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
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