Problems on H.C.F and L.C.M Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case. 48 52 35 22 48 52 35 22 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (132 - 62), (237 - 132) and (237 - 62) = H.C.F. of 70, 105 and 175 = 35.
Problems on H.C.F and L.C.M Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is: 200 40 80 120 200 40 80 120 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x, 4x and 5x.Then, their L.C.M. = 60x.So, 60x = 2400 or x = 40. The numbers are (3 x 40), (4 x 40) and (5 x 40).Hence, required H.C.F. = 40.
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: 408 308 508 208 408 308 508 208 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = (11 x 7700/275) = 308.
Problems on H.C.F and L.C.M If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M. 2474 2574 2674 2774 2474 2574 2674 2774 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP HCF * LCM = 84942, because we knowProduct of two numbers = Product of HCF and LCMLCM = 84942/33 = 2574
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12, 15, 18 and 27. 8720 9720 9620 8760 8720 9720 9620 8760 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F of two numbers is 8. Which of the following can never be their L.C.M? 48 56 24 60 48 56 24 60 ANSWER DOWNLOAD EXAMIANS APP
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