Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4 and 3 is : 13 23 33 3 13 23 33 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is : 1 -2 2 -1 1 -2 2 -1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least multiple of 23,which when divided by 18,21 and 24 leaves remainders 7,10 and 13 respectively. 3024 3036 3002 3013 3024 3036 3002 3013 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 23 27 25 21 23 27 25 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 505 606 707 404 505 606 707 404 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are? 800,500 820,369 820,360 700,400 800,500 820,369 820,360 700,400 ANSWER DOWNLOAD EXAMIANS APP
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