Problems on H.C.F and L.C.M What is the greatest number which divides 29, 32, 38 and leaves same remainder in each case? 2 3 4 5 2 3 4 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are? 700,400 820,369 800,500 820,360 700,400 820,369 800,500 820,360 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 389 216 443 548 389 216 443 548 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the length 7 m, 3 m 85 cm, 12 m 95 cm is : 15 cm 35 cm 25 cm 42 cm 15 cm 35 cm 25 cm 42 cm ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are 12, 24, 36 10, 20, 30 4, 8, 12 5, 10, 15 12, 24, 36 10, 20, 30 4, 8, 12 5, 10, 15 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1075 1095 1080 1085 1075 1095 1080 1085 ANSWER DOWNLOAD EXAMIANS APP