Problems on H.C.F and L.C.M he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 910 91 1911 1001 910 91 1911 1001 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 2025 and their HCF is 15 their LCM is: 2010 2040 150 135 2010 2040 150 135 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 99 100 98 97 99 100 98 97 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
Problems on H.C.F and L.C.M Three men start together to travel the same way around a circular track of 11 kilometers in circumference. Their speeds are 4, 5 and 8 kilometers per hour respectively. When will they meet at a starti 220 hours 22 hours 12 hours 11 hours 220 hours 22 hours 12 hours 11 hours ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the H.C.F of 204, 1190 and 1445? 17 204 34 85 17 204 34 85 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 18 16 17 19 18 16 17 19 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
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