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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:

1001
1911
910
91

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

8
6
4
2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)                                 = H.C.F. of 48, 92 and 140 = 4.

Problems on H.C.F and L.C.M
Two numbers are in the ratio 3 : 4. If their L.C.M. is 96. what is sum of the numbers?

56
48
84
76

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number

110
360
420
180

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420

Problems on H.C.F and L.C.M
Find largest number of 4 digits divisible by 12, 15, 18, 27 ?

12765
10478
11340
9720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The largest 4 digit number is 9999.We know that , if LCM of given numbers divide a number N , then N is exactly divisible by all the given numbers .LCM of 12,15,18,27 is 540.On dividing 9999 by 540 we get 279 as remainder.Therefore number =9999 - 279 =9720.

Problems on H.C.F and L.C.M
Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case

7
13
9
4

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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