Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12,15 and 18 is : 10020 10080 10015 10010 10020 10080 10015 10010 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP NA
Problems on H.C.F and L.C.M The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is 46 90 70 10 46 90 70 10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M. 2474 2774 2674 2574 2474 2774 2674 2574 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP HCF * LCM = 84942, because we knowProduct of two numbers = Product of HCF and LCMLCM = 84942/33 = 2574
Problems on H.C.F and L.C.M Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respestively. 3013 3002 3036 3024 3013 3002 3036 3024 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 10:13:17 hrs 8:27:12 hrs 9:22:08 hrs 7:25:14 hrs 10:13:17 hrs 8:27:12 hrs 9:22:08 hrs 7:25:14 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
Problems on H.C.F and L.C.M Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively? 260 169 143 221 260 169 143 221 ANSWER DOWNLOAD EXAMIANS APP
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