Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 427 869 859 4320 427 869 859 4320 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 420 110 180 360 420 110 180 360 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
Problems on H.C.F and L.C.M The least number of five digits that have 144 their HCF is? 10085 10075 10070 10080 10085 10075 10070 10080 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number? 7 5 13 11 7 5 13 11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The maximum number of student amoung them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : 910 1001 1911 91 910 1001 1911 91 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ? 15 10 4 16 15 10 4 16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes, they will toll together 30 + 1 = 16 times. 2
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