Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 869 4320 859 427 869 4320 859 427 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ? 770 420 630 540 770 420 630 540 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 12, 18, 21, 30 2 | 12 - 18 - 21 - 30 ---------------------------- = 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15 ---------------------------- Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5 = 630.
Problems on H.C.F and L.C.M Find the least number which when divide by 2, 3, 4, 5 and 6 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 7 leaves no remainder? 154 126 119 210 154 126 119 210 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 601/55 11/120 55/601 120/11 601/55 11/120 55/601 120/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number of five digits which is exactly divisible by 12, 15 and 18? 10025 11080 10080 1080 10025 11080 10080 1080 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The largest four – digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is 9834 8739 9893 9831 9834 8739 9893 9831 ANSWER DOWNLOAD EXAMIANS APP
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