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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the HCF of 2.1, 1.05 and 0.63

2.21
3.21
0.21
1.21

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

To solve this question quickly, first remove decimal by multiplying each term with 100,Then terms become 210, 105, 63Then HCF of above terms is 21, So Answer is 0.21

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

1015
689
432
268

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015

Problems on H.C.F and L.C.M
The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers.

2 and 4
8 and 10
8 and 6
6 and 4

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Let the leas number of six digits. which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2 be N. The sum of the digits in N is

6
4
5
3

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the greatest possible length which can be used to measure exactly the length 4 m 95 cm . , 9 m and 16 m 65 cm.

42 cm.
35 cm
55 cm.
45 cm.

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Which of the following has the most number of divisors?

182
176
99
101

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Option A, 176 = 1 x 2 x 2 x 2 x 2 x 11.Option B, 182 = 1 x 2 x 7 x 13. Option C, 99 = 1 x 3 x 3 x 11. Option D, 101 = 1 x 101.Divisors of 99 are 1, 3, 9, 11, 33, 99.Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176. Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.Hence, 176 have the most number of divisors.

MORE MCQ ON Problems on H.C.F and L.C.M

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