Problems on H.C.F and L.C.M Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number? 103 107 113 101 103 107 113 101 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 24 22 21 23 24 22 21 23 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: 1449 1440 1439 1459 1449 1440 1439 1459 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: equal to their H. 1 F 117 Cannot be calculated equal to their H. 1 F 117 Cannot be calculated ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: 299 345 276 322 299 345 276 322 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, the numbers are (23 x 13) and (23 x 14). Larger number = (23 x 14) = 322.
Problems on H.C.F and L.C.M The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers. 8 and 6 6 and 4 2 and 4 8 and 10 8 and 6 6 and 4 2 and 4 8 and 10 ANSWER DOWNLOAD EXAMIANS APP
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