Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 30 20 10 40 30 20 10 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M Find the L.C.M. of 16, 24, 36 and 54. 189 228 432 321 189 228 432 321 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2 | 16 - 24 - 36 - 54----------------------------- 2 | 8 - 12 - 18 - 27----------------------------- 2 | 4 - 6 - 9 - 27 --------------------------- 2 | 2 - 3 - 9 - 27 -------------------------- 2 | 1 - 3 - 9 - 27-------------------------- 3 | 1 - 1 - 3 - 9--------------------------- 3 | 1 - 1 - 1 - 3 L.C.M. = 2 x 2 x 2 x 3 x 3 x 2 x 3 = 432.
Problems on H.C.F and L.C.M Find the lowest common multiple of 24, 36 and 40. 240 480 360 120 240 480 360 120 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2 | 24 - 36 - 40 -------------------- 2 | 12 - 18 - 20 -------------------- 2 | 6 - 9 - 10 ------------------- 3 | 3 - 9 - 5 ------------------- | 1 - 3 - 5 L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.
Problems on H.C.F and L.C.M How many minimum number's of whole square slabs are required for paving the floor 12.96 meters long and 3.84 meters side? 256 216 192 108 256 216 192 108 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 6, 7, 8, 9 and 10 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 19 leaves no remainder? 5035 5016 5073 5054 5035 5016 5073 5054 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm 255 cm 265 cm 285 cm 275 cm 255 cm 265 cm 285 cm 275 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Convert first all terms into cm.i.e. 1575 cm, 1125cm, 765cm.Now whenever we need to calculate this type of question, we need to find the HCF.HCF of above terms is 255.
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