Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 30 10 40 20 30 10 40 20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively? 260 143 221 169 260 143 221 169 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4 and 3 is : 13 23 3 33 13 23 3 33 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 12 and their difference is 12. The numbers are: 94, 106 66, 78 70, 82 84, 96 94, 106 66, 78 70, 82 84, 96 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12,15,18 and 27. 8720 6720 7720 9720 8720 6720 7720 9720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . Required number = (9999-279) = 9720.
Problems on H.C.F and L.C.M The H.C.F of 2923 and 3239 is : 79 37 47 73 79 37 47 73 ANSWER DOWNLOAD EXAMIANS APP
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