Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 10 40 30 20 10 40 30 20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M The least number which when divided by 8, 12 and 16, leave in each remainder 3, is? 70 51 69 71 70 51 69 71 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is? 1494 1349 1994 1496 1494 1349 1994 1496 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 4128/4386 to its lowest terms 13/18 13/17 14/13 16/17 13/18 13/17 14/13 16/17 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respestively. 3036 3002 3013 3024 3036 3002 3013 3024 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case 9 13 4 7 9 13 4 7 ANSWER DOWNLOAD EXAMIANS APP
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