Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 40 30 10 20 40 30 10 20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12,15,18 and 27. 9720 6720 8720 7720 9720 6720 8720 7720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . Required number = (9999-279) = 9720.
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 17/29 23/37 11/13 31/45 17/29 23/37 11/13 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M The least number which when divided by 5,6,7 And 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is : 1683 3363 2523 1677 1683 3363 2523 1677 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which of the following integers has the most number of divisors? 182 99 176 101 182 99 176 101 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three men start together to travel the same way around a circular track of 11 kilometers in circumference. Their speeds are 4, 5 and 8 kilometers per hour respectively. When will they meet at a starti 11 hours 12 hours 22 hours 220 hours 11 hours 12 hours 22 hours 220 hours ANSWER DOWNLOAD EXAMIANS APP
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