Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 20 10 30 40 20 10 30 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M The L.C.M of 22, 54, 108, 135 and 198 is 11880 1980 5940 330 11880 1980 5940 330 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 185 101 107 111 185 101 107 111 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M The G.C.D. of 1.08, 0.36 and 0.9 is: 0.18 0.03 0.108 0.9 0.18 0.03 0.108 0.9 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given numbers are 1.08, 0.36 and 0.90. H.C.F. of 108, 36 and 90 is 18, H.C.F. of given numbers = 0.18.
Problems on H.C.F and L.C.M A rectangular courtyard 3.78 meters long 5.25 meters wide is to be paved exactly with square tiles, all of the same size. what is the largest size of the tile which could be used for the purpose? 21 cms 42 cms 14 cms None of these 21 cms 42 cms 14 cms None of these ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A heap of stones can be made up into groups of 21. When made up into groups of 16, 20, 25 and 45 there are 3 stones left in each case. How many stones at least can there be in the heap? 7203 2403 3603 4803 7203 2403 3603 4803 ANSWER DOWNLOAD EXAMIANS APP
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