Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 20 30 10 40 20 30 10 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M A rectangular courtyard 3.78 metres long and 2.25 metres wide is to be paved exactly with square title, all of the same size. What is the largest size of the tile which could be used for the purpose 21 cms None of these 11 cms 42 cms 21 cms None of these 11 cms 42 cms ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 4128/4386 to its lowest terms 14/13 13/18 16/17 13/17 14/13 13/18 16/17 13/17 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M How many minimum number's of whole square slabs are required for paving the floor 12.96 meters long and 3.84 meters side? 216 192 256 108 216 192 256 108 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm 255 cm 285 cm 265 cm 275 cm 255 cm 285 cm 265 cm 275 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Convert first all terms into cm.i.e. 1575 cm, 1125cm, 765cm.Now whenever we need to calculate this type of question, we need to find the HCF.HCF of above terms is 255.
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively. 445 379 127 221 445 379 127 221 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 _______1651 ) 2032 ( 1 1651 1651_______ 381 ) 1651 ( 4 1524_________ 127 ) 381 ( 3 381 0Required number = 127.
EXAMIANS