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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

20
10
40
30

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.

Problems on H.C.F and L.C.M
The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is

12
4
6
8

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The largest four – digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is

9834
8739
9831
9893

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number,which when divided by 48,60,72,108 and 140 leaves 38,50,62,98 and 130 as remainder respectively, is :

11115
15120
15210
15110

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is

360
180
540
1260

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Which of the following has the most number of divisors?

99
101
182
176

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Option A, 176 = 1 x 2 x 2 x 2 x 2 x 11.Option B, 182 = 1 x 2 x 7 x 13. Option C, 99 = 1 x 3 x 3 x 11. Option D, 101 = 1 x 101.Divisors of 99 are 1, 3, 9, 11, 33, 99.Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176. Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.Hence, 176 have the most number of divisors.

MORE MCQ ON Problems on H.C.F and L.C.M

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