Problems on H.C.F and L.C.M Find the smallest number which when increased by 5, divisible by 6, 9, 15, 20 and 24? 366 344 355 377 366 344 355 377 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: 1983 1383 1183 1683 1983 1383 1183 1683 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.
Problems on H.C.F and L.C.M A room is 4 meters 37 cm long and 3 meters 23cm broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose? 485 431 381 391 485 431 381 391 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 21 24 17 31 21 24 17 31 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M Find the largest number of four digits which is exactly divisible by 27,18,12,15 9720 11720 8720 10720 9720 11720 8720 10720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27-18-12-15 is 540.After dividing 9999 by 540 we get 279 remainder.So answer will be 9999-279 = 9720
Problems on H.C.F and L.C.M Three men start together to travel the same way around a circular track of 11 kilometers in circumference. Their speeds are 4, 5 and 8 kilometers per hour respectively. When will they meet at a starti 11 hours 22 hours 12 hours 220 hours 11 hours 22 hours 12 hours 220 hours ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS