Problems on H.C.F and L.C.M Find the H.C.F. of 513, 1134 and 1215. 27 42 58 63 27 42 58 63 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1134 ) 1215 ( 1 1134 --------- 81 ) 1134 ( 14 81 --------- 324 324 --------- x ---------- H.C.F. of 1134 and 1215 is 81.So, Required H.C.F. = H.C.F. of 513 and 81. ______81 ) 513 ( 6 __486____ 27) 81 ( 3 81 0H.C.F. of given numbers = 27.
Problems on H.C.F and L.C.M Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case 9 7 13 4 9 7 13 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 2 4 8 6 2 4 8 6 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 427 859 4320 869 427 859 4320 869 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the HCF of 2.1, 1.05 and 0.63 3.21 1.21 2.21 0.21 3.21 1.21 2.21 0.21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP To solve this question quickly, first remove decimal by multiplying each term with 100,Then terms become 210, 105, 63Then HCF of above terms is 21, So Answer is 0.21
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 601/55 55/601 11/120 120/11 601/55 55/601 11/120 120/11 ANSWER DOWNLOAD EXAMIANS APP
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