Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 693. If one of the numbers is 77,find the other. 99 109 89 79 99 109 89 79 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = 11 X 693 = 99 77
Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M A, B and C start at the same time in the direction to run around a circular stadium. A completes a round in 252 seconds and C in 198 seconds, all starting at the same point. after what time will they 45 minutes 26 minutes 18 econds 46 minutes 12 econds 42 minutes 36 econds 45 minutes 26 minutes 18 econds 46 minutes 12 econds 42 minutes 36 econds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is: 8 6 12 4 8 6 12 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F of 2923 and 3239 is : 47 73 37 79 47 73 37 79 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: 1183 1683 1383 1983 1183 1683 1383 1983 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.
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