Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 505 404 707 606 505 404 707 606 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
Problems on H.C.F and L.C.M A, B and C start at the same time in the direction to run around a circular stadium. A completes a round in 252 seconds and C in 198 seconds, all starting at the same point. after what time will they 42 minutes 36 econds 46 minutes 12 econds 45 minutes 26 minutes 18 econds 42 minutes 36 econds 46 minutes 12 econds 45 minutes 26 minutes 18 econds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which of the following integers has the most number of divisors? 176 101 182 99 176 101 182 99 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 20, 25, 35 and 40 leaves remainders 14, 19, 29, and 34 respectively . 1394 1384 1295 1354 1394 1384 1295 1354 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number of four digits which is exactly divisible by 27,18,12,15 8720 9720 10720 11720 8720 9720 10720 11720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27-18-12-15 is 540.After dividing 9999 by 540 we get 279 remainder.So answer will be 9999-279 = 9720
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 420 180 360 110 420 180 360 110 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
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