Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12, 15, 18 and 27. 8760 8720 9620 9720 8760 8720 9620 9720 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm 255 cm 285 cm 265 cm 275 cm 255 cm 285 cm 265 cm 275 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Convert first all terms into cm.i.e. 1575 cm, 1125cm, 765cm.Now whenever we need to calculate this type of question, we need to find the HCF.HCF of above terms is 255.
Problems on H.C.F and L.C.M The greatest number of four digits that have 144 for their HCF is? 9935 9903 9936 9930 9935 9903 9936 9930 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is: 25 cm 55 cm 35 cm 45 cm 25 cm 55 cm 35 cm 45 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.
Problems on H.C.F and L.C.M What is the least number of that is exactly divisible by 4, 12, 15, and 18? 150 110 180 60 150 110 180 60 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of (4, 12, 15, and 18) 2|4 12 15 18 3|2 6 15 9 2|2 2 5 3 1 1 5 3 Least number which is exactly divisible by 4,12,15 and 18 is =180
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 17 24 21 31 17 24 21 31 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
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