Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 55/601 120/11 11/120 601/55 55/601 120/11 11/120 601/55 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 25 21 27 23 25 21 27 23 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: F equal to their H. 1 117 Cannot be calculated F equal to their H. 1 117 Cannot be calculated ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is 180 360 1260 540 180 360 1260 540 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 8 : 27 : 12 hrs. 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 8 : 27 : 12 hrs. 5 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case? 19 18 17 16 19 18 17 16 ANSWER DOWNLOAD EXAMIANS APP
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