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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is :

4
6
3
5

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4 and 3 is :

33
23
13
3

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:

28
32
64
40

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

1045
364
777
1745

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.

Problems on H.C.F and L.C.M
If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.

2674
2574
2474
2774

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

HCF * LCM = 84942, because we knowProduct of two numbers = Product of HCF and LCMLCM = 84942/33 = 2574

Problems on H.C.F and L.C.M
There are four prime numbers written in ascending order of magnitude. The product of the first three is 7429 and of the last three is 12673. Find the fourth number?

31
17
23
29

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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