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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is :

6
5
3
4

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the largest number of four digits exactly divisible by 12, 15, 18 and 27.

8760
9620
9720
8720

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case

4
7
13
9

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The greatest number which can divide 1356,1868 and 2764 leaving the same remainder 12 in each case, is :

260
124
64
124

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

10
20
30
40

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.

Problems on H.C.F and L.C.M
What is the least number which when divided by 6, 9, 12 and 18 leaves remainder 4 in each care?

56
30
40
36

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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