Problems on H.C.F and L.C.M The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 0, 62,98 and 130 as remainders respectively is . 15110 15120 15210 11115 15110 15120 15210 11115 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 693 . If one of the numbers is 77, find the other . 88 95 99 77 88 95 99 77 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 23 27 21 25 23 27 21 25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to: 55/601 601/55 11/120 120/11 55/601 601/55 11/120 120/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The HCF of two numbers is 42 and the other two factors of their LCM are 11 and 12. What is the largest number. 504 480 450 462 504 480 450 462 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 20 40 10 30 20 40 10 30 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
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