Problems on H.C.F and L.C.M Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder . 1683 3683 2683 4683 1683 3683 2683 4683 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5,6,7,8 = 840. Required number is of the form 840k + 3 Least value of k for which (840k + 3) is divisible by 9 is k = 2. Required number = (840 X 2 + 3)=1683
Problems on H.C.F and L.C.M Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ? 10 15 4 16 10 15 4 16 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are 4, 8, 12 5, 10, 15 10, 20, 30 12, 24, 36 4, 8, 12 5, 10, 15 10, 20, 30 12, 24, 36 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The HCF of two numbers is 42 and the other two factors of their LCM are 11 and 12. What is the largest number. 480 450 462 504 480 450 462 504 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12, 15 and 18, is: 10020 10010 10080 10015 10020 10010 10080 10015 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again? 242 seconds 246 seconds 240 seconds 243 seconds 242 seconds 246 seconds 240 seconds 243 seconds ANSWER DOWNLOAD EXAMIANS APP
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