Problems on H.C.F and L.C.M The greatest number which can divide 1356,1868 and 2764 leaving the same remainder 12 in each case, is : 260 124 124 64 260 124 124 64 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers are in the ratio 3 : 4. If their L.C.M. is 96. what is sum of the numbers? 56 48 76 84 56 48 76 84 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number of that is exactly divisible by 4, 12, 15, and 18? 180 110 150 60 180 110 150 60 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of (4, 12, 15, and 18) 2|4 12 15 18 3|2 6 15 9 2|2 2 5 3 1 1 5 3 Least number which is exactly divisible by 4,12,15 and 18 is =180
Problems on H.C.F and L.C.M The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is: 36 18 24 48 36 18 24 48 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.So, the numbers 12 and 16.L.C.M. of 12 and 16 = 48.
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is : 6 5 4 3 6 5 4 3 ANSWER DOWNLOAD EXAMIANS APP
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