Problems on H.C.F and L.C.M What is the least number which when divided by 8, 12, 18 and 24 leaves the remainders 4, 8, 14 and 20 respectively? None 78 58 68 None 78 58 68 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 10:13:17 hrs 8:27:12 hrs 9:22:08 hrs 7:25:14 hrs 10:13:17 hrs 8:27:12 hrs 9:22:08 hrs 7:25:14 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
Problems on H.C.F and L.C.M The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 10, then their difference is: 10 46 70 90 10 46 70 90 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively? 143 260 169 221 143 260 169 221 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The leas number which when divided by 5, 6, 7 and 8 leaves a remainder 3 but when divided by 9 leaves no remainder, is : 3363 2523 1677 1683 3363 2523 1677 1683 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 24 22 23 21 24 22 23 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
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