Problems on H.C.F and L.C.M Find he smallest number of five digits exactly divisible by 16, 24, 36 and 54 . 10688 9868 9368 10368 10688 9868 9368 10368 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are? 700,400 800,500 820,360 820,369 700,400 800,500 820,360 820,369 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which will divide 25, 73 and 97 as so to leave the same remainder in each case? 18 12 32 24 18 12 32 24 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 2 minute 48 seconds 4 minute 48 seconds 1 minute 48 seconds 3 minute 48 seconds 2 minute 48 seconds 4 minute 48 seconds 1 minute 48 seconds 3 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 18 17 19 16 18 17 19 16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: 1383 1683 1183 1983 1383 1683 1183 1983 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.
EXAMIANS