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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

8
6
4
2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)                                 = H.C.F. of 48, 92 and 140 = 4.

Problems on H.C.F and L.C.M
Find the least number which when divided by 20, 25, 35 and 40 leaves remainders 14, 19, 29, and 34 respectively .

1295
1394
1384
1354

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The largest four – digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is

9831
9893
9834
8739

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to:

601/55
120/11
55/601
11/120

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case.

22
35
48
52

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number =  H.C.F. of (132 - 62), (237 - 132) and (237 - 62)                                      =  H.C.F. of 70, 105 and 175 = 35.

Problems on H.C.F and L.C.M
A heap of stones can be made up into groups of 21. When made up into groups of 16, 20, 25 and 45 there are 3 stones left in each case. How many stones at least can there be in the heap?

3603
4803
2403
7203

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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