Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 4 6 8 2 4 6 8 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M In a school, the number of students in Sections A , B and C of 10th class are 70,98 and 126 respectively. Due to overload of student in each class , the administration wants to increase the number roo 28 17 14 21 28 17 14 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The number students in each room = HCF of 70,98 and 126 =14 In each room , maximum 14 students can be seated. Total number students = 70 + 98 +126 =294 Number of rooms required = 294/14 =21
Problems on H.C.F and L.C.M How many minimum number's of whole square slabs are required for paving the floor 12.96 meters long and 3.84 meters side? 192 216 256 108 192 216 256 108 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is: 180 540 360 1260 180 540 360 1260 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three friends Raju , Ramesh and Sunil start running around a circular stadium and complete a single round in 24 s, 36 s and 40 s, respectively. After how many minutes will they meet against at the sta 7 minutes 5 minutes 6 minutes 8 minutes 7 minutes 5 minutes 6 minutes 8 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 24 = 3 × 2 × 2 × 2 = 3 × 2³ 36 = 3 × 3 × 2 × 2 = 3² × 2²and 40 = 2 × 2 × 2 × 5 = 5¹ × 23 LCM of 24, 36 and 40 = 3² × 2³ × 5 = 9 × 8 × 5 = 360Hence, they will meet again at the starting point after 360 s, i.e., 6 min
Problems on H.C.F and L.C.M Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ? 15 10 16 4 15 10 16 4 ANSWER DOWNLOAD EXAMIANS APP
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