Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 2 6 8 4 2 6 8 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is: 40 64 32 28 40 64 32 28 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Least perfect square number, exactly divisible by 21, 36 and 56 is? 3600 504 7056 441 3600 504 7056 441 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The maximum number of student amoung them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : 910 91 1001 1911 910 91 1001 1911 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is : 6 3 4 5 6 3 4 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 127 129 133 131 127 129 133 131 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
EXAMIANS