Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 4 2 6 8 4 2 6 8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 22 23 21 24 22 23 21 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M Find the H.C.F of 204, 1190 and 1445? 204 17 85 34 204 17 85 34 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is: 108 48 12 84 108 48 12 84 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that will divide 172, 205 and 304 so as to leave the same remainder in each case? None of these 33 99 66 None of these 33 99 66 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The greatest number that will divide 172,205 and 304 leaving the same remainder in each case is HCF ((205-172), (304-205), (304-172)) = HCF of 33, 99, and 132 33=31x11 99=3 x 3 x 11 132=3 x 2 x 2 x11 Required number =3 x 11=33
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: Cannot be calculated 117 F equal to their H. 1 Cannot be calculated 117 F equal to their H. 1 ANSWER DOWNLOAD EXAMIANS APP
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