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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

6
4
2
8

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)                                 = H.C.F. of 48, 92 and 140 = 4.

Problems on H.C.F and L.C.M
The least number of five digits which is exactly divisible by 12,15 and 18 is :

10015
10020
10080
10010

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 NA

Problems on H.C.F and L.C.M
Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

18002
18004
18000
17004

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:

28
40
32
64

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to

35
37
42
30

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find largest number of 4 digits divisible by 12, 15, 18, 27 ?

10478
9720
11340
12765

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The largest 4 digit number is 9999.We know that , if LCM of given numbers divide a number N , then N is exactly divisible by all the given numbers .LCM of 12,15,18,27 is 540.On dividing 9999 by 540 we get 279 as remainder.Therefore number =9999 - 279 =9720.

MORE MCQ ON Problems on H.C.F and L.C.M

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