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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

8
4
6
2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)                                 = H.C.F. of 48, 92 and 140 = 4.

Problems on H.C.F and L.C.M
The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 10, then their difference is:

46
10
90
70

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number of four digits which is divisible by 4, 6, 8 and 10 is?

1095
1085
1075
1080

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?

15
16
10
4

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes, they will toll together 30 + 1 = 16 times. 2

Problems on H.C.F and L.C.M
The greatest number of four digits that have 144 for their HCF is?

9936
9930
9935
9903

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the greatest possible length which can be used to measure exactly the lengths 4 m 95 cm, 9 m and 16 m 65 cm.

55 cm
25 cm
35 cm
45 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required length = H.C.F. of 495 cm, 900 cm and 1665 cm.          495 = 3² x 5 x 11, 900 = 2² x 3² x 5², 1665 = 3² x 5 x 37.      H.C.F. = 32 x 5 = 45.          Hence, required length = 45 cm.

MORE MCQ ON Problems on H.C.F and L.C.M

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