Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 6 4 2 8 6 4 2 8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 8:27:12 hrs 7:25:14 hrs 9:22:08 hrs 10:13:17 hrs 8:27:12 hrs 7:25:14 hrs 9:22:08 hrs 10:13:17 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
Problems on H.C.F and L.C.M Which of the following integers has the most number of divisors? 99 101 182 176 99 101 182 176 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The G.C.D. of 1.08, 0.36 and 0.9 is: 0.108 0.18 0.9 0.03 0.108 0.18 0.9 0.03 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given numbers are 1.08, 0.36 and 0.90. H.C.F. of 108, 36 and 90 is 18, H.C.F. of given numbers = 0.18.
Problems on H.C.F and L.C.M The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is: 40 64 28 32 40 64 28 32 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 1911 1001 910 91 1911 1001 910 91 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS