Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 8 2 6 4 8 2 6 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1095 1075 1085 1080 1095 1075 1085 1080 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which of the following integers has the most number of divisors? 101 176 99 182 101 176 99 182 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 4128/4386 to its lowest terms 14/13 16/17 13/17 13/18 14/13 16/17 13/17 13/18 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder? 121 123 112 116 121 123 112 116 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123
Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 606 505 707 404 606 505 707 404 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
EXAMIANS