Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 4 6 2 8 4 6 2 8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is: 8 6 4 12 8 6 4 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other 66 77 55 88 66 77 55 88 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99) = 77
Problems on H.C.F and L.C.M HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is? 36 132 264 66 36 132 264 66 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The greatest number which can divide 1356,1868 and 2764 leaving the same remainder 12 in each case, is : 260 64 124 124 260 64 124 124 ANSWER DOWNLOAD EXAMIANS APP
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