Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 16 18 17 19 16 18 17 19 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M The product of two digits number is 2160 and their HCF is 12. The numbers are: (72,30) (36,60) (96,25) (12,180) (72,30) (36,60) (96,25) (12,180) ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to: 601/55 11/120 120/11 55/601 601/55 11/120 120/11 55/601 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 1095/1168 when expressed in simplest form is: 13/16 15/16 17/26 25/26 13/16 15/16 17/26 25/26 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 125 126 127 128 125 126 127 128 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5)= H.C.F. of 1651 and 2032 = 127.
Problems on H.C.F and L.C.M The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of t 3 min 1 min None 2 min 3 min 1 min None 2 min ANSWER DOWNLOAD EXAMIANS APP
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