Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 18 17 19 16 18 17 19 16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 91 910 1001 1911 91 910 1001 1911 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 23 21 25 27 23 21 25 27 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
Problems on H.C.F and L.C.M The Smallest number which when diminished by 7, is divisible by 12,16,18,21 and 28 is : 1008 1022 1015 1032 1008 1022 1015 1032 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case? 4 6 3 5 4 6 3 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case? 1026 1030 1020 1022 1026 1030 1020 1022 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS