Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 17 16 19 18 17 16 19 18 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is? 1349 1494 1496 1994 1349 1494 1496 1994 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the smallest number which when increased by 5, divisible by 6, 9, 15, 20 and 24? 377 366 344 355 377 366 344 355 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 1/3, 5/6, 5/4, 10/7 is: 10/11 10/7 11/10 10 10/11 10/7 11/10 10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which will divide 25, 73 and 97 as so to leave the same remainder in each case? 32 18 24 12 32 18 24 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M In a school, the number of students in Sections A , B and C of 10th class are 70,98 and 126 respectively. Due to overload of student in each class , the administration wants to increase the number roo 28 17 14 21 28 17 14 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The number students in each room = HCF of 70,98 and 126 =14 In each room , maximum 14 students can be seated. Total number students = 70 + 98 +126 =294 Number of rooms required = 294/14 =21
EXAMIANS