Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 19 17 16 18 19 17 16 18 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 55/601 11/120 601/55 120/11 55/601 11/120 601/55 120/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 each divisible by each one of 24, 32, 36 and 54 is : 4320 859 427 869 4320 859 427 869 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 455, 117, 338 is: 10670 106470 104670 107470 10670 106470 104670 107470 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three numbers are in the ratio of 2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is: 20 40 60 30 20 40 60 30 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 427 859 4320 869 427 859 4320 869 ANSWER DOWNLOAD EXAMIANS APP
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