Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 16 19 17 18 16 19 17 18 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M Find he smallest number of five digits exactly divisible by 16, 24, 36 and 54 . 9368 10688 9868 10368 9368 10688 9868 10368 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 707 505 404 606 707 505 404 606 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
Problems on H.C.F and L.C.M A merchant has three different types of milk: 435 liters, 493 liters and 551 liters. Find the least number of casks of equal size required to store all the milk without mixing. 47 61 51 45 47 61 51 45 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 128 125 127 126 128 125 127 126 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5)= H.C.F. of 1651 and 2032 = 127.
Problems on H.C.F and L.C.M Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is: 200 120 80 40 200 120 80 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x, 4x and 5x.Then, their L.C.M. = 60x.So, 60x = 2400 or x = 40. The numbers are (3 x 40), (4 x 40) and (5 x 40).Hence, required H.C.F. = 40.
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