Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is: 14400 6400 1600 3600 14400 6400 1600 3600 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 420 110 360 180 420 110 360 180 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
Problems on H.C.F and L.C.M The product of two numbers is 2025 and their HCF is 15 their LCM is: 2010 2040 135 150 2010 2040 135 150 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 17/29 11/13 23/37 31/45 17/29 11/13 23/37 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case? 1022 1030 1026 1020 1022 1030 1026 1020 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 10 20 40 30 10 20 40 30 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
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