Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is: 1600 3600 14400 6400 1600 3600 14400 6400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 55/601 11/120 601/55 120/11 55/601 11/120 601/55 120/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is 1008 1032 1022 1015 1008 1032 1022 1015 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M L.C.M. of two prime numbers x and y (x > y) is 161 The value of 3y – x is: -2 -1 1 2 -2 -1 1 2 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number of four digits which is divisible by 15, 24, 40 and 75 is : 9400 9800 9600 9000 9400 9800 9600 9000 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, 12 : 31 am 9 : 31 am 10 : 31 am 11 : 31 am 12 : 31 am 9 : 31 am 10 : 31 am 11 : 31 am ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 60 and 62 seconds is 1860 seconds1860/60 = 31 minutesThey will beep together at 10:31 a.m.Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
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