Problems on H.C.F and L.C.M What is the HCF of 2/3, 4/9 and 6/5 2/45 8/45 4/15 7/45 2/45 8/45 4/15 7/45 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The leas number which when divided by 5, 6, 7 and 8 leaves a remainder 3 but when divided by 9 leaves no remainder, is : 3363 1683 2523 1677 3363 1683 2523 1677 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 each divisible by each one of 24, 32, 36 and 54 is : 4320 869 859 427 4320 869 859 427 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case? 17 18 19 16 17 18 19 16 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 10:13:17 hrs 8:27:12 hrs 9:22:08 hrs 7:25:14 hrs 10:13:17 hrs 8:27:12 hrs 9:22:08 hrs 7:25:14 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 360 110 180 420 360 110 180 420 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
EXAMIANS