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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?

3
4
6
5

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

216
389
548
443

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.

Problems on H.C.F and L.C.M
Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respectively.

3036
3002
3013
3024

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least multiple of 23,which when divided by 18,21 and 24 leaves remainders 7,10 and 13 respectively.

3036
3024
3013
3002

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
What is the HCF of 2/3, 4/9 and 6/5

2/45
7/45
8/45
4/15

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

777
1045
364
1745

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.

MORE MCQ ON Problems on H.C.F and L.C.M

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