Problems on H.C.F and L.C.M An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent? 4 6 3 5 4 6 3 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is: 12 108 48 84 12 108 48 84 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 8 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 5 : 27 : 12 hrs. 8 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 5 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ? 770 420 630 540 770 420 630 540 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 12, 18, 21, 30 2 | 12 - 18 - 21 - 30 ---------------------------- = 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15 ---------------------------- Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5 = 630.
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 40 30 20 10 40 30 20 10 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 23 27 25 21 23 27 25 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
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