Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 101 107 111 185 101 107 111 185 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ? 10 4 15 16 10 4 15 16 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is 4 6 8 12 4 6 8 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the length 7 m, 3 m 85 cm, 12 m 95 cm is : 15 cm 42 cm 35 cm 25 cm 15 cm 42 cm 35 cm 25 cm ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 1095/1168 when expressed in simplest form is: 25/26 13/16 17/26 15/16 25/26 13/16 17/26 15/16 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three numbers are in the ratio 3:4:5 and their L.C.M is 2400. Their H.C.F is: 80 40 200 120 80 40 200 120 ANSWER DOWNLOAD EXAMIANS APP
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