Problems on H.C.F and L.C.M The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: 1383 1683 1183 1983 1383 1683 1183 1983 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.
Problems on H.C.F and L.C.M A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to 35 30 37 42 35 30 37 42 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case? 1022 1030 1020 1026 1022 1030 1020 1026 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively. 1494 1194 1294 1394 1494 1194 1294 1394 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6. Required number = (L.C.M. of 20,25,35,40) – 6 =1394.
Problems on H.C.F and L.C.M he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 1911 1001 910 91 1911 1001 910 91 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 17 24 31 21 17 24 31 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
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