Problems on H.C.F and L.C.M Three numbers are in the ratio of 2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is: 40 60 30 20 40 60 30 20 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 548 216 389 443 548 216 389 443 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is: 4 8 12 6 4 8 12 6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other 77 55 66 88 77 55 66 88 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99) = 77
Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 98 99 100 97 98 99 100 97 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
Problems on H.C.F and L.C.M The H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is 180 540 1260 360 180 540 1260 360 ANSWER DOWNLOAD EXAMIANS APP
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