Problems on H.C.F and L.C.M Find the H.C.F of 54/9, 3 9/17 and 36/51? 6/153 17 6 17/6 6/153 17 6 17/6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: 299 345 276 322 299 345 276 322 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, the numbers are (23 x 13) and (23 x 14). Larger number = (23 x 14) = 322.
Problems on H.C.F and L.C.M Find the H.C.F. of 513, 1134 and 1215. 27 42 58 63 27 42 58 63 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1134 ) 1215 ( 1 1134 --------- 81 ) 1134 ( 14 81 --------- 324 324 --------- x ---------- H.C.F. of 1134 and 1215 is 81.So, Required H.C.F. = H.C.F. of 513 and 81. ______81 ) 513 ( 6 __486____ 27) 81 ( 3 81 0H.C.F. of given numbers = 27.
Problems on H.C.F and L.C.M Find the least number which when divide by 2, 3, 4, 5 and 6 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 7 leaves no remainder? 126 210 119 154 126 210 119 154 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16,20, and 24, is : 3600 1600 11400 6400 3600 1600 11400 6400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 23/37 31/45 11/13 17/29 23/37 31/45 11/13 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
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