Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: 1 117 equal to their H. F Cannot be calculated 1 117 equal to their H. F Cannot be calculated ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder? 121 116 123 112 121 116 123 112 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123
Problems on H.C.F and L.C.M Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is : 6 4 3 5 6 4 3 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A gardener was asked a plant flowers in a row containing equal number of plants. He tried to plant 6, 8, 10 and 12 in each row, but 5 plants left in each case. When he planted 13 in a row, no plant wa 845 245 485 125 845 245 485 125 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 1/3, 5/6, 5/4, 10/7 is: 10/11 11/10 10/7 10 10/11 11/10 10/7 10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively? 260 143 169 221 260 143 169 221 ANSWER DOWNLOAD EXAMIANS APP
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