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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Product of two co-prime numbers is 117. Their L.C.M should be:

Cannot be calculated
equal to their H.
117
1
F

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which when divided by 5,6,7 And 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is :

1683
3363
1677
2523

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

107
111
185
101

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.

Problems on H.C.F and L.C.M
A. B. and C. start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds.all starting at the same point.

26 minutes 18 seconds
46 minutes 12 seconds.
42 minutes 36 seconds
45 minutes

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The ratio of numbers is 3:4 and their H.C.F is 4. Their L.C.M is:

48
12
16
24

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

17004
18004
18000
18002

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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