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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Product of two co-prime numbers is 117. Their L.C.M should be:

Cannot be calculated
F
equal to their H.
1
117

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The largest four – digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is

9893
8739
9831
9834

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively.

1194
1294
1394
1494

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6.    Required number = (L.C.M. of 20,25,35,40) – 6 =1394.

Problems on H.C.F and L.C.M
The H.C.F. of two numbers is 11 and their L.C.M. is 693. If one of the numbers is 77,find the other.

99
109
79
89

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Other number = 11 X 693   = 99                              77                            

Problems on H.C.F and L.C.M
If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other

88
77
55
66

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99)                              = 77

Problems on H.C.F and L.C.M
Let the leas number of six digits. which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2 be N. The sum of the digits in N is

3
4
5
6

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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