Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: equal to their H. Cannot be calculated F 117 1 equal to their H. Cannot be calculated F 117 1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the smallest number of five digits exactly divisible by 16,24,36 and 54. 10568 10368 10268 10468 10568 10368 10268 10468 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Smallest number of five digits is 10000. Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432, On dividing 10000 by 432,we get 64 as remainder. Required number = 10000 +( 432 – 64 ) = 10368.
Problems on H.C.F and L.C.M There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number? 5 11 13 7 5 11 13 7 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers are in the ratio of 15 : 11. If their H.C. F. is 13, Find he numbers . 175 and 123 195 and 143 185 and 133 195 and 163 175 and 123 195 and 143 185 and 133 195 and 163 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case? 1026 1022 1030 1020 1026 1022 1030 1020 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that will divided 43,91 and 183 so as to leave the same remainder in each case 13 4 7 9 13 4 7 9 ANSWER DOWNLOAD EXAMIANS APP