Problems on H.C.F and L.C.M The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is: 48 36 24 18 48 36 24 18 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.So, the numbers 12 and 16.L.C.M. of 12 and 16 = 48.
Problems on H.C.F and L.C.M The largest four-digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case,is : 8739 9831 9834 9893 8739 9831 9834 9893 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: 1745 364 1045 777 1745 364 1045 777 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.
Problems on H.C.F and L.C.M Find the least number which when divided by 26, 36 and 46 leaves the remainders 12, 22 and 32 respectively. 10570 17050 10750 10075 10570 17050 10750 10075 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 455, 117, 338 is: 107470 106470 104670 10670 107470 106470 104670 10670 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 21 17 31 24 21 17 31 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
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