Problems on H.C.F and L.C.M H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is: 360 180 1260 540 360 180 1260 540 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 7 : 27 : 12 hrs. 6 : 27 : 12 hrs. 5 : 27 : 12 hrs. 8 : 27 : 12 hrs. 7 : 27 : 12 hrs. 6 : 27 : 12 hrs. 5 : 27 : 12 hrs. 8 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 6 5 4 3 6 5 4 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 91 1001 1911 910 91 1001 1911 910 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers are in the ratio of 15 : 11. If their H.C. F. is 13, Find he numbers . 185 and 133 195 and 143 195 and 163 175 and 123 185 and 133 195 and 143 195 and 163 175 and 123 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the smallest number of five digits exactly divisible by 16,24,36 and 54. 10568 10368 10268 10468 10568 10368 10268 10468 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Smallest number of five digits is 10000. Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432, On dividing 10000 by 432,we get 64 as remainder. Required number = 10000 +( 432 – 64 ) = 10368.
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