Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 693. If one of the numbers is 77,find the other. 109 79 89 99 109 79 89 99 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = 11 X 693 = 99 77
Problems on H.C.F and L.C.M The product of two numbers is 2025 and their HCF is 15 their LCM is: 2010 2040 150 135 2010 2040 150 135 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 23 21 24 22 23 21 24 22 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case? 5 6 3 4 5 6 3 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 1/3, 5/6, 5/4, 10/7 is: 10/11 10 11/10 10/7 10/11 10 11/10 10/7 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS