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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
252 can be expressed as a product of primes as:

2 x 3 x 3 x 3 x 7
2 x 2 x 3 x 3 x 7
3 x 3 x 3 x 3 x 7
2 x 2 x 2 x 3 x 7

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

Problems on H.C.F and L.C.M
Find the least number which when divided by 26, 36 and 46 leaves the remainders 12, 22 and 32 respectively.

10075
10750
17050
10570

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:

91
1911
910
1001

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:

910
1001
91
1911

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.

2674
2474
2574
2774

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

HCF * LCM = 84942, because we knowProduct of two numbers = Product of HCF and LCMLCM = 84942/33 = 2574

Problems on H.C.F and L.C.M
H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is

540
1260
360
180

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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