Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M What is the least number of that is exactly divisible by 4, 12, 15, and 18? 150 110 180 60 150 110 180 60 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of (4, 12, 15, and 18) 2|4 12 15 18 3|2 6 15 9 2|2 2 5 3 1 1 5 3 Least number which is exactly divisible by 4,12,15 and 18 is =180
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1095 1080 1085 1075 1095 1080 1085 1075 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 455, 117, 338 is: 10670 104670 107470 106470 10670 104670 107470 106470 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is: 40 64 32 28 40 64 32 28 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: 1183 1983 1683 1383 1183 1983 1683 1383 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.
EXAMIANS