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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
252 can be expressed as a product of primes as:

3 x 3 x 3 x 3 x 7
2 x 3 x 3 x 3 x 7
2 x 2 x 2 x 3 x 7
2 x 2 x 3 x 3 x 7

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

Problems on H.C.F and L.C.M
The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is

427
869
859
4320

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are:

10, 20, 30
10, 20, 30
5, 10, 15
4, 8, 12

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is

1008
1015
1022
1032

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
LCM of 87 and 145 is:

435
48
1305
875

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find largest number of 4 digits divisible by 12, 15, 18, 27 ?

9720
12765
10478
11340

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The largest 4 digit number is 9999.We know that , if LCM of given numbers divide a number N , then N is exactly divisible by all the given numbers .LCM of 12,15,18,27 is 540.On dividing 9999 by 540 we get 279 as remainder.Therefore number =9999 - 279 =9720.

MORE MCQ ON Problems on H.C.F and L.C.M

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