Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is 46 70 10 90 46 70 10 90 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 16, 18, 20 and 2 leaves 4 as remainder in each case , but when divided by 7 leaves no. remainder 18000 17004 18002 18004 18000 17004 18002 18004 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 14. The least number which when diminished by 7 is divisible by 21, 28, 36 and 45 is? 1267 1265 68 1261 1267 1265 68 1261 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The G.C.D. of 1.08, 0.36 and 0.9 is: 0.18 0.108 0.03 0.9 0.18 0.108 0.03 0.9 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given numbers are 1.08, 0.36 and 0.90. H.C.F. of 108, 36 and 90 is 18, H.C.F. of given numbers = 0.18.
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1075 1095 1080 1085 1075 1095 1080 1085 ANSWER DOWNLOAD EXAMIANS APP
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