Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The least square number which divides 8, 12 and 18 is? 121 64 144 100 121 64 144 100 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number? 113 103 101 107 113 103 101 107 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 18004 18000 18002 17004 18004 18000 18002 17004 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the HCF of 2.1, 1.05 and 0.63 1.21 3.21 0.21 2.21 1.21 3.21 0.21 2.21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP To solve this question quickly, first remove decimal by multiplying each term with 100,Then terms become 210, 105, 63Then HCF of above terms is 21, So Answer is 0.21
Problems on H.C.F and L.C.M The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: 1440 1439 1449 1459 1440 1439 1449 1459 ANSWER DOWNLOAD EXAMIANS APP
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