Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 2 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The least number which when divided by 5,6,7 And 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is : 2523 1677 1683 3363 2523 1677 1683 3363 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 15, 25, 40 and 75 is: 9400 9600 9800 9000 9400 9600 9800 9000 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which can divide 1356,1868 and 2764 leaving the same remainder 12 in each case, is : 124 124 260 64 124 124 260 64 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two digits number is 2160 and their HCF is 12. The numbers are: (96,25) (36,60) (72,30) (12,180) (96,25) (36,60) (72,30) (12,180) ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder . 2683 4683 1683 3683 2683 4683 1683 3683 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5,6,7,8 = 840. Required number is of the form 840k + 3 Least value of k for which (840k + 3) is divisible by 9 is k = 2. Required number = (840 X 2 + 3)=1683
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