Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 97 98 99 100 97 98 99 100 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
Problems on H.C.F and L.C.M Find the least number which when divided by 20, 25, 35 and 40 leaves remainders 14, 19, 29, and 34 respectively . 1384 1295 1354 1394 1384 1295 1354 1394 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which can divide 1356, 1868 and 2764 leaving the same remainder 12 in each case, is: 124 260 64 156 124 260 64 156 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which of the following integers has the most number of divisors? 176 101 182 99 176 101 182 99 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is 1032 1015 1008 1022 1032 1015 1008 1022 ANSWER DOWNLOAD EXAMIANS APP