Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M Find the greatest possible length which can be used to measure exactly the length 4 m 95 cm . , 9 m and 16 m 65 cm. 42 cm. 45 cm. 35 cm 55 cm. 42 cm. 45 cm. 35 cm 55 cm. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M. 2774 2574 2474 2674 2774 2574 2474 2674 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP HCF * LCM = 84942, because we knowProduct of two numbers = Product of HCF and LCMLCM = 84942/33 = 2574
Problems on H.C.F and L.C.M The greatest number of four digits which is divisible by 15, 24, 40 and 75 is : 9800 9600 9400 9000 9800 9600 9400 9000 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 1095/1168 when expressed in simplest form is: 17/26 13/16 15/16 25/26 17/26 13/16 15/16 25/26 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12,15,18 and 27. 9720 8720 6720 7720 9720 8720 6720 7720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . Required number = (9999-279) = 9720.
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