Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 2 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 2 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M Find he smallest number of five digits exactly divisible by 16, 24, 36 and 54 . 9368 10688 10368 9868 9368 10688 10368 9868 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respectively. 3024 3013 3036 3002 3024 3013 3036 3002 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number of four digits which is exactly divisible by 27,18,12,15 10720 9720 8720 11720 10720 9720 8720 11720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27-18-12-15 is 540.After dividing 9999 by 540 we get 279 remainder.So answer will be 9999-279 = 9720
Problems on H.C.F and L.C.M Find the H.C.F. of 513, 1134 and 1215. 63 27 58 42 63 27 58 42 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1134 ) 1215 ( 1 1134 --------- 81 ) 1134 ( 14 81 --------- 324 324 --------- x ---------- H.C.F. of 1134 and 1215 is 81.So, Required H.C.F. = H.C.F. of 513 and 81. ______81 ) 513 ( 6 __486____ 27) 81 ( 3 81 0H.C.F. of given numbers = 27.
Problems on H.C.F and L.C.M Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are: 4, 8, 12 10, 20, 30 10, 20, 30 5, 10, 15 4, 8, 12 10, 20, 30 10, 20, 30 5, 10, 15 ANSWER DOWNLOAD EXAMIANS APP
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