Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 360 180 420 110 360 180 420 110 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
Problems on H.C.F and L.C.M Find the H.C.F of 54/9, 3 9/17 and 36/51? 6 17/6 17 6/153 6 17/6 17 6/153 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12, 15 and 18, is: 10010 10015 10080 10020 10010 10015 10080 10020 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers. 8 and 6 2 and 4 6 and 4 8 and 10 8 and 6 2 and 4 6 and 4 8 and 10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 18002 18004 18000 17004 18002 18004 18000 17004 ANSWER DOWNLOAD EXAMIANS APP
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