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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
252 can be expressed as a product of primes as:

2 x 3 x 3 x 3 x 7
2 x 2 x 2 x 3 x 7
2 x 2 x 3 x 3 x 7
3 x 3 x 3 x 3 x 7

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

Problems on H.C.F and L.C.M
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

101
111
107
185

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.

Problems on H.C.F and L.C.M
The H.C.F of 204, 1190 and 1445 is:

19
18
17
21

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the largest number of four digits exactly divisible by 12, 15, 18 and 27.

8720
8760
9720
9620

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number?

113
103
101
107

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag

5 : 27 : 12 hrs.
8 : 27 : 12 hrs.
7 : 27 : 12 hrs.
6 : 27 : 12 hrs.

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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