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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
252 can be expressed as a product of primes as:

2 x 2 x 2 x 3 x 7
2 x 2 x 3 x 3 x 7
2 x 3 x 3 x 3 x 7
3 x 3 x 3 x 3 x 7

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

Problems on H.C.F and L.C.M
Find the least number which when divided by 16, 18, 20 and 2 leaves 4 as remainder in each case , but when divided by 7 leaves no. remainder

18000
18004
18002
17004

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm

255 cm
285 cm
275 cm
265 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Convert first all terms into cm.i.e. 1575 cm, 1125cm, 765cm.Now whenever we need to calculate this type of question, we need to find the HCF.HCF of above terms is 255.

Problems on H.C.F and L.C.M
The maximum number of student amoung them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is :

910
1001
91
1911

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is

540
180
1260
360

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
LCM of 1/3, 5/6, 5/4, 10/7 is:

10
10/11
10/7
11/10

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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