Problems on H.C.F and L.C.M Find the greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively. 221 445 127 379 221 445 127 379 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 _______1651 ) 2032 ( 1 1651 1651_______ 381 ) 1651 ( 4 1524_________ 127 ) 381 ( 3 381 0Required number = 127.
Problems on H.C.F and L.C.M The least square number which divides 8, 12 and 18 is? 144 121 100 64 144 121 100 64 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M The H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is 360 1260 180 540 360 1260 180 540 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A rectangular courtyard 3.78 metres long and 2.25 metres wide is to be paved exactly with square title, all of the same size. What is the largest size of the tile which could be used for the purpose 21 cms 11 cms 42 cms None of these 21 cms 11 cms 42 cms None of these ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 4 minute 48 seconds 2 minute 48 seconds 3 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds 2 minute 48 seconds 3 minute 48 seconds 1 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
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