Problems on H.C.F and L.C.M Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is: 40 200 80 120 40 200 80 120 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x, 4x and 5x.Then, their L.C.M. = 60x.So, 60x = 2400 or x = 40. The numbers are (3 x 40), (4 x 40) and (5 x 40).Hence, required H.C.F. = 40.
Problems on H.C.F and L.C.M The least number,which when divided by 48,60,72,108 and 140 leaves 38,50,62,98 and 130 as remainder respectively, is : 15210 15120 15110 11115 15210 15120 15110 11115 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A. B. and C. start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds.all starting at the same point. 42 minutes 36 seconds 26 minutes 18 seconds 45 minutes 46 minutes 12 seconds. 42 minutes 36 seconds 26 minutes 18 seconds 45 minutes 46 minutes 12 seconds. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is: 24 18 36 48 24 18 36 48 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.So, the numbers 12 and 16.L.C.M. of 12 and 16 = 48.
Problems on H.C.F and L.C.M Find the largest number which divides 62,132,237 to leave the same reminder 30 25 35 None of these 30 25 35 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Trick is HCF of (237-132), (132-62), (237-62)= HCF of (70,105,175) = 35
Problems on H.C.F and L.C.M Find the greatest number of four digits which when divided by 10, 15, 21 and 28 leaves 4, 9, 15 and 22 as remainders respectively? 9864 9666 9664 9654 9864 9666 9664 9654 ANSWER DOWNLOAD EXAMIANS APP
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